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Speed, Time & Distance
Quantitative Aptitude · Maths Bookwise · Work & Motion
Useful for: SSC CGL
BOOK-GUIDED ORIGINAL SSC MATHS PRACTICE — Speed, Time & Distance
FOUNDATION
Distance = speed × time.
METHOD
Identify the quantities given, choose the exact relationship, calculate in the same unit, then check the answer against the question.
WORKED EXAMPLE 1
A vehicle travels at 106 km/h for 3 hours. Find distance (km).
Distance = speed × time = 106 × 3 = 318 km.
WORKED EXAMPLE 2
A vehicle travels at 76 km/h for 12 hours. Find distance (km).
Distance = speed × time = 76 × 12 = 912 km.
IMPORTANT EXCEPTION / COMMON TRAP
Ensure both speed and time use compatible units.
QUICK REVISION
Distance = speed × time.
SEE MORE: https://study.kundali-iq.com/ssc-maths/speed/
For complete timed maths practice, use SSC CGL Test Series → New Maths 100 Mixed Sets or Chapter-wise sets. These are independent original questions, not copied previous-year questions.
Practice MCQs
A vehicle travels at 106 km/h for 3 hours. Find distance (km).
- 339
- 360
- 297
- 318
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Answer: (d) 318. Distance = speed × time = 106 × 3 = 318 km.
A vehicle travels at 76 km/h for 12 hours. Find distance (km).
- 852
- 1032
- 972
- 912
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Answer: (d) 912. Distance = speed × time = 76 × 12 = 912 km.
A vehicle travels at 29 km/h for 8 hours. Find distance (km).
- 232
- 262
- 247
- 217
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Answer: (a) 232. Distance = speed × time = 29 × 8 = 232 km.
A vehicle travels at 103 km/h for 11 hours. Find distance (km).
- 1133
- 1058
- 1283
- 1208
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Answer: (a) 1133. Distance = speed × time = 103 × 11 = 1133 km.
A vehicle travels at a constant speed of 72 km/h for 25 minutes. How far does it travel
- 25 km
- 30 km
- 36 km
- 45 km
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Answer: (b) 30 km. Distance = 72 × (25/60) = 30 km.
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