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Coordinate Geometry

Quantitative Aptitude · Maths Bookwise · Geometry & Mensuration

Useful for: SSC CGL

BOOK-GUIDED ORIGINAL SSC MATHS PRACTICE — Coordinate Geometry

FOUNDATION

Midpoint = ((x1+x2)/2, (y1+y2)/2).

METHOD

Identify the quantities given, choose the exact relationship, calculate in the same unit, then check the answer against the question.

WORKED EXAMPLE 1

Find the x-coordinate of the midpoint of (40, 11) and (16, -9).

Midpoint x = (40+16)/2 = 28. The y-values do not affect x.

WORKED EXAMPLE 2

Find the x-coordinate of the midpoint of (10, -10) and (2, 2).

Midpoint x = (10+2)/2 = 6. The y-values do not affect x.

IMPORTANT EXCEPTION / COMMON TRAP

Do not swap the x- and y-coordinates.

QUICK REVISION

Midpoint = ((x1+x2)/2, (y1+y2)/2).

SEE MORE: https://study.kundali-iq.com/ssc-maths/coordinate/

For complete timed maths practice, use SSC CGL Test Series → New Maths 100 Mixed Sets or Chapter-wise sets. These are independent original questions, not copied previous-year questions.

Practice MCQs

  1. Find the x-coordinate of the midpoint of (40, 11) and (16, -9).

    1. 30
    2. 29
    3. 27
    4. 28

    Read chapter notes · Similar questions

    Show answer

    Answer: (d) 28. Midpoint x = (40+16)/2 = 28. The y-values do not affect x.

  2. Find the x-coordinate of the midpoint of (10, -10) and (2, 2).

    1. 8
    2. 7
    3. 6
    4. 5

    Read chapter notes · Similar questions

    Show answer

    Answer: (c) 6. Midpoint x = (10+2)/2 = 6. The y-values do not affect x.

  3. Find the x-coordinate of the midpoint of (42, 7) and (2, 7).

    1. 23
    2. 22
    3. 24
    4. 21

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    Show answer

    Answer: (b) 22. Midpoint x = (42+2)/2 = 22. The y-values do not affect x.

  4. Find the x-coordinate of the midpoint of (48, 8) and (24, -13).

    1. 38
    2. 40
    3. 34
    4. 36

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    Answer: (d) 36. Midpoint x = (48+24)/2 = 36. The y-values do not affect x.

  5. What is the distance between points (0, 0) and (6, 8) on the coordinate plane

    1. 10 units
    2. 12 units
    3. 14 units
    4. 8 units

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    Show answer

    Answer: (a) 10 units. Distance = √[(6 − 0)² + (8 − 0)²] = √100 = 10 units.

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Notes and questions are written by Kundali IQ for practice. They are not official papers; always check the latest official notification for the syllabus and pattern.