Home › Free notes › Class 10 Mathematics › Surface Areas and Volumes
Surface Areas and Volumes – Class 10 Mathematics notes, important questions and MCQs
NCERT Class 10 Mathematics, chapter 12. Notes, key terms, important questions with answers and MCQs.
Chapter overview
Solids like a toy (cone on a hemisphere) or a capsule (cylinder with two hemispheres) are combinations of basic solids. Add only the surfaces that are visible; volumes simply add up.
Basic solids
- Cuboid: V = lbh; TSA = 2(lb + bh + hl).
- Cylinder: V = πr²h; CSA = 2πrh.
- Cone: V = ⅓πr²h; CSA = πrl with l = √(r² + h²).
- Sphere: V = (4/3)πr³; SA = 4πr². Hemisphere: V = (2/3)πr³; CSA = 2πr².
Combinations
- Surface area of a combined solid = sum of the outer (exposed) surfaces only.
- Volume of a combined solid = sum of volumes of the parts.
- When one solid is melted and recast, the volume stays the same.
Key terms
- Curved surface area
- area of the curved part only
- Total surface area
- curved area plus the flat faces
- Slant height
- l = √(r² + h²) of a cone
Formulas
- Cone V = ⅓πr²h, CSA = πrl
- Sphere V = (4/3)πr³, SA = 4πr²
- Hemisphere V = (2/3)πr³, TSA = 3πr²
- Cylinder V = πr²h, TSA = 2πr(r + h)
Important questions with answers
Two cubes of volume 64 cm³ each are joined end to end. Find the surface area of the cuboid formed.2 marks
Side = 4 cm. Cuboid is 8 × 4 × 4. SA = 2(8×4 + 4×4 + 4×8) = 2(32 + 16 + 32) = 160 cm².
A solid toy is a hemisphere of radius 3.5 cm topped by a cone of the same radius and total height 15.5 cm. Find its total surface area.3 marks
Cone height = 15.5 − 3.5 = 12 cm; slant height l = √(12² + 3.5²) = 12.5 cm. TSA = πrl + 2πr² = (22/7) × 3.5 × 12.5 + 2 × (22/7) × 12.25 = 137.5 + 77 = 214.5 cm².
A metallic sphere of radius 4.2 cm is melted and recast into a cylinder of radius 6 cm. Find the height of the cylinder. Also say which quantity stays the same and why.5 marks
Volume stays the same because the same metal is reshaped (no metal is lost). (4/3)π(4.2)³ = π(6)²h, so h = (4/3 × 74.088)/36 = 98.784/36 = 2.744 cm.
Quick revision
- Visible surfaces add for area; all parts add for volume.
- Volume is conserved on melting.
- l² = r² + h² for a cone.
Exam tips
- Do not add the hidden circular face where two solids join.
- For melting/recasting questions, equate volumes and keep the units the same.
Practice MCQs
Volume of a cube of side 4 cm is
- 16 cm³
- 64 cm³
- 48 cm³
- 96 cm³
Show answer
Answer: (b) 64 cm³. 4³ = 64 cm³.
Curved surface area of a hemisphere of radius r is
- πr²
- 2πr²
- 3πr²
- 4πr²
Show answer
Answer: (b) 2πr². Half of the sphere's 4πr².
Slant height of a cone with r = 6 cm, h = 8 cm is
- 14 cm
- 10 cm
- 7 cm
- 12 cm
Show answer
Answer: (b) 10 cm. √(36 + 64) = 10 cm.
Two cubes of side 5 cm are joined end to end. TSA of the cuboid is
- 250 cm²
- 300 cm²
- 200 cm²
- 150 cm²
Show answer
Answer: (a) 250 cm². Cuboid 10 × 5 × 5: 2(50 + 25 + 50) = 250 cm².
A cone and a cylinder have the same base and height. Their volumes are in the ratio
- 1 : 3
- 3 : 1
- 1 : 2
- 2 : 3
Show answer
Answer: (a) 1 : 3. ⅓πr²h : πr²h.
Volume of a sphere of radius 3 cm (in terms of π) is
- 36π cm³
- 27π cm³
- 12π cm³
- 108π cm³
Show answer
Answer: (a) 36π cm³. (4/3)π × 27 = 36π.
A metal sphere of radius 6 cm is melted into a wire of radius 0.2 cm. The length of the wire is
- 36 m
- 7.2 m
- 72 m
- 720 m
Show answer
Answer: (c) 72 m. (4/3)π × 216 = π × 0.04 × h ⇒ h = 7200 cm = 72 m.
A toy is a cone of radius 3.5 cm on a hemisphere of the same radius; total height is 15.5 cm. Its total surface area is
- 291.5 cm²
- 154 cm²
- 77 cm²
- 214.5 cm²
Show answer
Answer: (d) 214.5 cm². h_cone = 12, l = 12.5; πrl + 2πr² = 137.5 + 77 = 214.5 cm².
All chapters of Class 10 Mathematics
Written by Kundali IQ from standard, well-established facts to help with revision. This is not an official NCERT publication; always read your textbook too.