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Statistics – Class 10 Mathematics notes, important questions and MCQs
NCERT Class 10 Mathematics, chapter 13. Notes, key terms, important questions with answers and MCQs.
Chapter overview
For grouped data we find the mean, mode and median of frequency distributions, and use the relation between the three.
Mean of grouped data
- Direct method: x̄ = Σfᵢxᵢ / Σfᵢ, where xᵢ is the class mark.
- Assumed mean method: x̄ = a + Σfᵢdᵢ / Σfᵢ with dᵢ = xᵢ − a.
- Step deviation: x̄ = a + h × Σfᵢuᵢ / Σfᵢ with uᵢ = (xᵢ − a)/h.
Mode and median
- Mode = l + [(f₁ − f₀)/(2f₁ − f₀ − f₂)] × h (modal class has the highest frequency).
- Median = l + [(n/2 − cf)/f] × h (median class contains the n/2-th observation).
- Empirical relation: 3 Median = Mode + 2 Mean.
Key terms
- Class mark
- (upper limit + lower limit)/2
- Modal class
- the class with the highest frequency
- Cumulative frequency
- running total of frequencies
Formulas
- Mode = l + [(f₁ − f₀)/(2f₁ − f₀ − f₂)] × h
- Median = l + [(n/2 − cf)/f] × h
- 3 Median = Mode + 2 Mean
Important questions with answers
Write the empirical relationship between mean, median and mode, and find the mode if mean = 30 and median = 32.2 marks
Mode = 3 Median − 2 Mean = 96 − 60 = 36.
Find the class mark of the classes 10–25 and 35–55.3 marks
Class mark = (lower limit + upper limit)/2: (10 + 25)/2 = 17.5 and (35 + 55)/2 = 45.
For the data: classes 0–10, 10–20, 20–30, 30–40, 40–50 with frequencies 5, 8, 15, 16, 6, find the median.5 marks
N = 50, N/2 = 25. Cumulative frequencies: 5, 13, 28, 44, 50. Median class is 20–30 (cf just above 25). l = 20, cf = 13, f = 15, h = 10. Median = l + [(N/2 − cf)/f] × h = 20 + (12/15) × 10 = 20 + 8 = 28.
Quick revision
- Mean uses class marks.
- Modal class = highest frequency; median class = where cf first reaches n/2.
- Mode = 3 Median − 2 Mean.
Exam tips
- In the median formula, cf is the cumulative frequency of the class BEFORE the median class.
- Make classes continuous (e.g. 9.5–19.5) before using formulas if they are given as 10–19, 20–29.
Practice MCQs
Class mark of 10–20 is
- 10
- 15
- 20
- 30
Show answer
Answer: (b) 15. (10 + 20)/2 = 15.
The class with the highest frequency is called the
- median class
- mean class
- modal class
- first class
Show answer
Answer: (c) modal class. Mode is the most frequent value.
If mean = 20 and median = 18, then mode =
- 14
- 16
- 22
- 24
Show answer
Answer: (a) 14. 3 × 18 − 2 × 20 = 14.
Mean of 2, 4, 6, 8, 10 with frequencies 1, 2, 3, 2, 1 is
- 7
- 5
- 6
- 6.5
Show answer
Answer: (c) 6. Σfx = 2 + 8 + 18 + 16 + 10 = 54; Σf = 9; mean = 6.
In the median formula, cf stands for
- cumulative frequency of the class before the median class
- frequency of the median class
- total frequency
- class width
Show answer
Answer: (a) cumulative frequency of the class before the median class. Standard notation.
Which measure is found graphically from the point where the two ogives meet?
- mean
- mode
- median
- range
Show answer
Answer: (c) median. The x-coordinate of the meeting point is the median.
For a distribution, l = 40, f₁ = 12, f₀ = 8, f₂ = 6, h = 10. Mode =
- 45
- 44
- 46
- 42
Show answer
Answer: (b) 44. 40 + (4/10) × 10 = 44.
n = 50, median class 30–40, cf before it 22, its frequency 10. Median =
- 30
- 32
- 35
- 33
Show answer
Answer: (d) 33. 30 + [(25 − 22)/10] × 10 = 33.
All chapters of Class 10 Mathematics
Written by Kundali IQ from standard, well-established facts to help with revision. This is not an official NCERT publication; always read your textbook too.