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Remainders & Divisibility
Quantitative Aptitude · Maths Bookwise · Number System
Useful for: SSC CGL
BOOK-GUIDED ORIGINAL SSC MATHS PRACTICE — Remainders & Divisibility
FOUNDATION
N = divisor × quotient + remainder; 0 ≤ remainder < divisor.
METHOD
Identify the quantities given, choose the exact relationship, calculate in the same unit, then check the answer against the question.
WORKED EXAMPLE 1
What remainder is left when 627 is divided by 32?
627 = 32 × 19 + 19; hence remainder = 19.
WORKED EXAMPLE 2
What remainder is left when 1582 is divided by 22?
1582 = 22 × 71 + 20; hence remainder = 20.
IMPORTANT EXCEPTION / COMMON TRAP
Never report a remainder equal to the divisor.
QUICK REVISION
N = divisor × quotient + remainder; 0 ≤ remainder < divisor.
SEE MORE: https://study.kundali-iq.com/ssc-maths/number/
For complete timed maths practice, use SSC CGL Test Series → New Maths 100 Mixed Sets or Chapter-wise sets. These are independent original questions, not copied previous-year questions.
Practice MCQs
What remainder is left when 627 is divided by 32?
- 18
- 20
- 21
- 19
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Answer: (d) 19. 627 = 32 × 19 + 19; hence remainder = 19.
What remainder is left when 1582 is divided by 22?
- 20
- 19
- 21
- 22
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Answer: (a) 20. 1582 = 22 × 71 + 20; hence remainder = 20.
What remainder is left when 1580 is divided by 19?
- 2
- 3
- 4
- 5
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Answer: (b) 3. 1580 = 19 × 83 + 3; hence remainder = 3.
What remainder is left when 2286 is divided by 40?
- 7
- 8
- 6
- 5
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Answer: (c) 6. 2286 = 40 × 57 + 6; hence remainder = 6.
What remainder is left when 137 is divided by 9
- 2
- 1
- 3
- 8
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Answer: (a) 2. 137 = 9 × 15 + 2, so the remainder is 2.
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