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Elementary Probability
Quantitative Aptitude · Maths Bookwise · Data & Reasoning
Useful for: SSC CGL
BOOK-GUIDED ORIGINAL SSC MATHS PRACTICE — Elementary Probability
FOUNDATION
P(event) = favourable outcomes / total equally likely outcomes.
METHOD
Identify the quantities given, choose the exact relationship, calculate in the same unit, then check the answer against the question.
WORKED EXAMPLE 1
A bag has 68 red and 102 blue balls. One is picked uniformly at random. Find the probability of red (in %).
Total outcomes = 68+102=170. P(red)=68/170=4/10. In percent = 40%.
WORKED EXAMPLE 2
A bag has 78 red and 182 blue balls. One is picked uniformly at random. Find the probability of red (in %).
Total outcomes = 78+182=260. P(red)=78/260=3/10. In percent = 30%.
IMPORTANT EXCEPTION / COMMON TRAP
Probabilities lie between 0 and 1 inclusive.
QUICK REVISION
P(event) = favourable outcomes / total equally likely outcomes.
SEE MORE: https://study.kundali-iq.com/ssc-maths/probability/
For complete timed maths practice, use SSC CGL Test Series → New Maths 100 Mixed Sets or Chapter-wise sets. These are independent original questions, not copied previous-year questions.
Practice MCQs
A bag has 68 red and 102 blue balls. One is picked uniformly at random. Find the probability of red (in %).
- 44
- 40
- 42
- 38
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Answer: (b) 40. Total outcomes = 68+102=170. P(red)=68/170=4/10. In percent = 40%.
A bag has 78 red and 182 blue balls. One is picked uniformly at random. Find the probability of red (in %).
- 30
- 32
- 34
- 28
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Show answer
Answer: (a) 30. Total outcomes = 78+182=260. P(red)=78/260=3/10. In percent = 30%.
A bag has 280 red and 120 blue balls. One is picked uniformly at random. Find the probability of red (in %).
- 66
- 78
- 74
- 70
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Answer: (d) 70. Total outcomes = 280+120=400. P(red)=280/400=14/20. In percent = 70%.
A bag has 28 red and 7 blue balls. One is picked uniformly at random. Find the probability of red (in %).
- 75
- 85
- 80
- 90
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Answer: (c) 80. Total outcomes = 28+7=35. P(red)=28/35=4/5. In percent = 80%.
When two fair dice are rolled, what is the probability that their sum is 7
- 1/9
- 1/12
- 1/6
- 1/3
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Answer: (c) 1/6. There are 6 favourable ordered pairs out of 36 equally likely outcomes; probability = 6/36 = 1/6.
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Notes and questions are written by Kundali IQ for practice. They are not official papers; always check the latest official notification for the syllabus and pattern.