Compound Interest

BOOK-GUIDED ORIGINAL SSC MATHS PRACTICE — Compound Interest

FOUNDATION

Amount = P(1 + r/100)^n for annual compounding.

METHOD

Identify the quantities given, choose the exact relationship, calculate in the same unit, then check the answer against the question.

WORKED EXAMPLE 1

Find compound interest (₹) on ₹23600 at 25% annually for 2 years.

Amount = 23600×(125/100)² = ₹36875. CI = amount−principal = ₹13275.

WORKED EXAMPLE 2

Find compound interest (₹) on ₹2000 at 10% annually for 2 years.

Amount = 2000×(110/100)² = ₹2420. CI = amount−principal = ₹420.

IMPORTANT EXCEPTION / COMMON TRAP

The compounding period and rate must use matching units.

QUICK REVISION

Amount = P(1 + r/100)^n for annual compounding.

SEE MORE: https://study.kundali-iq.com/ssc-maths/compound_interest/

For complete timed maths practice, use SSC CGL Test Series → New Maths 100 Mixed Sets or Chapter-wise sets. These are independent original questions, not copied previous-year questions.

Practice MCQs

1. Find compound interest (₹) on ₹23600 at 25% annually for 2 years.

   1. 13275
   2. 15045
   3. 12390
   4. 14160

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   Answer: (a) 13275. Amount = 23600×(125/100)² = ₹36875. CI = amount−principal = ₹13275.

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2. Find compound interest (₹) on ₹2000 at 10% annually for 2 years.

   1. 420
   2. 392
   3. 448
   4. 476

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   Answer: (a) 420. Amount = 2000×(110/100)² = ₹2420. CI = amount−principal = ₹420.

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3. Find compound interest (₹) on ₹15200 at 20% annually for 2 years.

   1. 7133
   2. 6243
   3. 7578
   4. 6688

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   Answer: (d) 6688. Amount = 15200×(120/100)² = ₹21888. CI = amount−principal = ₹6688.

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4. Find compound interest (₹) on ₹16800 at 25% annually for 2 years.

   1. 10710
   2. 10080
   3. 9450
   4. 8820

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   Answer: (c) 9450. Amount = 16800×(125/100)² = ₹26250. CI = amount−principal = ₹9450.

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5. Find compound interest on ₹1100 at 20% p.a. for 2 years, compounded annually.

   1. 532.4
   2. 484
   3. 435.6
   4. 580.8

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   Answer: (b) 484. Amount = P(1+20/100)².

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6. Find compound interest on ₹1200 at 25% p.a. for 2 years, compounded annually.

   1. 675
   2. 607.5
   3. 810
   4. 742.5

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   Answer: (a) 675. Amount = P(1+25/100)².

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7. Find compound interest on ₹1300 at 10% p.a. for 2 years, compounded annually.

   1. 245.7
   2. 273
   3. 300.3
   4. 327.6

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   Answer: (b) 273. Amount = P(1+10/100)².

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8. Find compound interest on ₹1400 at 20% p.a. for 2 years, compounded annually.

   1. 739.2
   2. 677.6
   3. 554.4
   4. 616

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   Answer: (d) 616. Amount = P(1+20/100)².

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9. Find compound interest on ₹1500 at 25% p.a. for 2 years, compounded annually.

   1. 843.75
   2. 1012.5
   3. 759.38
   4. 928.12

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   Answer: (a) 843.75. Amount = P(1+25/100)².

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10. Find compound interest on ₹1600 at 10% p.a. for 2 years, compounded annually.

    1. 302.4
    2. 403.2
    3. 369.6
    4. 336

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    Answer: (d) 336. Amount = P(1+10/100)².

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11. Find compound interest on ₹1700 at 20% p.a. for 2 years, compounded annually.

    1. 673.2
    2. 897.6
    3. 822.8
    4. 748

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    Answer: (d) 748. Amount = P(1+20/100)².

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12. Find compound interest on ₹1800 at 25% p.a. for 2 years, compounded annually.

    1. 911.25
    2. 1113.75
    3. 1012.5
    4. 1215

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    Answer: (c) 1012.5. Amount = P(1+25/100)².

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13. Find compound interest on ₹1900 at 10% p.a. for 2 years, compounded annually.

    1. 438.9
    2. 478.8
    3. 359.1
    4. 399

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    Answer: (d) 399. Amount = P(1+10/100)².

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14. Find compound interest on ₹7500 at 25% p.a. for 2 years, compounded annually.

    1. 4640.62
    2. 5062.5
    3. 4218.75
    4. 3796.88

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    Answer: (c) 4218.75. Amount = P(1+25/100)².

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15. Find compound interest on ₹2000 at 20% p.a. for 2 years, compounded annually.

    1. 880
    2. 792
    3. 968
    4. 1056

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    Answer: (a) 880. Amount = P(1+20/100)².

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More topics in this chapter

• Profit and Loss
• Discount and Marked Price
• Simple Interest
• Partnership