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Math of Space: Surface Area and Volume – Class 9 Mathematics notes, important questions and MCQs
NCERT Class 9 Mathematics, chapter 14. Notes, key terms, important questions with answers and MCQs.
Chapter overview
Surface area is the total area covering a solid; volume is the space it fills. Each common solid has its own formulas.
Cuboid and cube
- Cuboid: TSA = 2(lb + bh + hl), lateral area = 2h(l + b), V = lbh.
- Cube: TSA = 6a², lateral area = 4a², V = a³.
Round solids
- Cylinder: CSA = 2πrh, TSA = 2πr(r + h), V = πr²h.
- Cone: CSA = πrl, TSA = πr(l + r), V = ⅓πr²h, l = √(r² + h²).
- Sphere: SA = 4πr², V = (4/3)πr³. Hemisphere: CSA = 2πr², TSA = 3πr², V = (2/3)πr³.
Key terms
- Lateral surface area
- area of the side faces only
- Capacity
- volume a container can hold (1 L = 1000 cm³)
- Slant height
- distance from the cone's vertex to the edge of its base
Formulas
- Cylinder V = πr²h
- Cone V = ⅓πr²h
- Sphere V = (4/3)πr³
- 1 m³ = 1000 L
Important questions with answers
Find the volume of a cube of edge 5 cm.2 marks
V = a³ = 125 cm³.
Find the curved surface area and volume of a cylinder of radius 7 cm and height 10 cm (π = 22/7).3 marks
CSA = 2πrh = 2 × (22/7) × 7 × 10 = 440 cm². V = πr²h = (22/7) × 49 × 10 = 1540 cm³.
A conical tent is 10 m high with base radius 24 m. Find its slant height, the canvas needed and the cost at ₹70 per m² (π = 22/7). Also find the air space inside.5 marks
Slant height l = √(24² + 10²) = √676 = 26 m. Canvas = CSA = πrl = (22/7) × 24 × 26 ≈ 1961.14 m². Cost ≈ 1961.14 × 70 ≈ ₹137,280. Air inside = ⅓πr²h = ⅓ × (22/7) × 576 × 10 ≈ 6034.3 m³.
Quick revision
- Cone volume is one-third of the cylinder with the same base and height.
- Hemisphere TSA = 3πr².
- 1000 cm³ = 1 litre.
Exam tips
- For open containers (no lid), leave out one face.
- If radius doubles, a sphere's volume becomes 8 times.
Practice MCQs
Volume of a cuboid 5 × 4 × 3 cm is
- 60 cm³
- 12 cm³
- 47 cm³
- 120 cm³
Show answer
Answer: (a) 60 cm³. 5 × 4 × 3.
Total surface area of a cube of side 3 cm is
- 27 cm²
- 54 cm²
- 36 cm²
- 18 cm²
Show answer
Answer: (b) 54 cm². 6 × 9.
1 litre equals
- 100 cm³
- 10 cm³
- 1000 cm³
- 1 m³
Show answer
Answer: (c) 1000 cm³. 1000 cm³.
CSA of a cylinder with r = 7 cm, h = 10 cm is
- 1540 cm²
- 220 cm²
- 440 cm²
- 154 cm²
Show answer
Answer: (c) 440 cm². 2 × 22/7 × 7 × 10 = 440.
Volume of a cone with r = 3 cm and h = 7 cm is
- 22 cm³
- 198 cm³
- 66 cm³
- 132 cm³
Show answer
Answer: (c) 66 cm³. ⅓ × 22/7 × 9 × 7 = 66.
Surface area of a sphere of radius 7 cm is
- 154 cm²
- 616 cm²
- 308 cm²
- 1437 cm²
Show answer
Answer: (b) 616 cm². 4 × 22/7 × 49 = 616.
If the radius of a sphere is doubled, its surface area becomes
- 2 times
- 4 times
- 8 times
- 16 times
Show answer
Answer: (b) 4 times. SA ∝ r².
A conical tent has radius 7 m and height 24 m. Canvas needed for its curved surface is
- 528 m²
- 550 m²
- 1232 m²
- 616 m²
Show answer
Answer: (b) 550 m². l = 25; πrl = 22/7 × 7 × 25 = 550.
All chapters of Class 9 Mathematics
Written by Kundali IQ from standard, well-established facts to help with revision. This is not an official NCERT publication; always read your textbook too.