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I'm Up and Down, and Round and Round – Class 9 Mathematics notes, important questions and MCQs
NCERT Class 9 Mathematics, chapter 5. Notes, key terms, important questions with answers and MCQs.
Chapter overview
This chapter studies circles: their parts, symmetry, chords, arcs and the angles they make. Key results connect chords with their distance from the centre, the angle at the centre with the angle on the circle, and the opposite angles of a cyclic quadrilateral.
Circle basics and chords
- Radius r, diameter 2r, chord (segment joining two points on the circle) and arc (part of the circle); the diameter is the longest chord.
- Every diameter is a line of symmetry of the circle, so a circle has infinitely many lines of symmetry.
- Exactly one circle passes through three points that are not on one line; no circle passes through three collinear points.
- The perpendicular from the centre to a chord bisects the chord, and the line joining the centre to a chord's midpoint is perpendicular to it.
Equal chords and distances
- Equal chords subtend equal angles at the centre, and chords subtending equal angles at the centre are equal.
- Equal chords are equidistant from the centre; a chord nearer the centre is longer.
- For a chord at distance d from the centre: chord length = 2√(r² − d²).
Angles and cyclic quadrilaterals
- The angle subtended by an arc at the centre is double the angle it subtends at any point on the remaining part of the circle.
- Angles in the same segment are equal; the angle in a semicircle is 90°.
- In a cyclic quadrilateral, each pair of opposite angles adds up to 180°; an exterior angle equals the interior opposite angle.
Key terms
- Chord
- a line segment joining any two points on a circle
- Arc
- a part of the circle between two points on it
- Concyclic points
- points that lie on the same circle
- Cyclic quadrilateral
- a quadrilateral whose four vertices lie on a circle
Formulas
- Chord length = 2√(r² − d²)
- Angle at centre = 2 × angle on the circle (same arc)
- Angle in a semicircle = 90°
- Opposite angles of a cyclic quadrilateral: ∠A + ∠C = 180°
Important questions with answers
Prove that the perpendicular from the centre of a circle to a chord bisects the chord.2 marks
Let OM be perpendicular from centre O to chord AB. In triangles OMA and OMB, OA = OB (radii), OM is common and ∠OMA = ∠OMB = 90°. By RHS congruence the triangles are congruent, so AM = BM, and OM bisects AB.
A chord of length 24 cm is drawn in a circle of radius 13 cm. Find its distance from the centre.3 marks
The perpendicular from the centre bisects the chord, so half the chord = 12 cm. Using Pythagoras in the right triangle formed with the radius: d² = 13² − 12² = 169 − 144 = 25, so d = 5 cm.
State and prove that the opposite angles of a cyclic quadrilateral are supplementary.5 marks
Theorem: the sum of either pair of opposite angles of a cyclic quadrilateral is 180°. Proof: let ABCD be a cyclic quadrilateral with centre O. Join OB and OD. Arc BCD subtends ∠BOD (say x) at the centre and ∠BAD at A on the remaining circle, so ∠BAD = x/2. Arc BAD subtends the reflex angle ∠BOD = 360° − x at the centre and ∠BCD at C, so ∠BCD = (360° − x)/2 = 180° − x/2. Adding, ∠BAD + ∠BCD = x/2 + 180° − x/2 = 180°. Similarly, ∠ABC + ∠ADC = 360° − 180° = 180°, since the angles of a quadrilateral add up to 360°. Hence the opposite angles are supplementary.
Quick revision
- Perpendicular from centre bisects a chord.
- Equal chords ↔ equal distances ↔ equal central angles.
- Central angle = 2 × inscribed angle; semicircle angle = 90°.
- Cyclic quadrilateral: opposite angles sum to 180°.
Exam tips
- In chord problems, draw the perpendicular from the centre; it creates a right triangle for Pythagoras.
- Mark the arc first, then identify which angle is at the centre and which is on the circle.
Practice MCQs
The longest chord of a circle is the
- radius
- arc
- diameter
- tangent
Show answer
Answer: (c) diameter. It passes through the centre.
The angle in a semicircle is
- 45°
- 60°
- 90°
- 180°
Show answer
Answer: (c) 90°. The arc is a semicircle, so the angle is half of 180°.
How many circles can pass through three non-collinear points
- none
- infinitely many
- two
- exactly one
Show answer
Answer: (d) exactly one. Their perpendicular bisectors meet at one centre.
A chord is 3 cm from the centre of a circle of radius 5 cm. Its length is
- 4 cm
- 6 cm
- 8 cm
- 10 cm
Show answer
Answer: (c) 8 cm. 2√(25 − 9) = 2 × 4 = 8 cm.
An arc subtends 100° at the centre. The angle it subtends at a point on the remaining circle is
- 80°
- 100°
- 200°
- 50°
Show answer
Answer: (d) 50°. It is half the central angle.
In a cyclic quadrilateral ABCD, ∠A = 70°. Then ∠C is
- 70°
- 90°
- 110°
- 20°
Show answer
Answer: (c) 110°. Opposite angles add up to 180°.
Two chords AB and CD are equal. Which statement must be true
- they are parallel
- they are diameters
- they intersect at the centre
- they are equidistant from the centre
Show answer
Answer: (d) they are equidistant from the centre. Equal chords are at equal distances from the centre.
An exterior angle of a cyclic quadrilateral is 105°. The interior opposite angle is
- 105°
- 75°
- 180°
- 52.5°
Show answer
Answer: (a) 105°. The exterior angle equals the interior opposite angle.
All chapters of Class 9 Mathematics
Written by Kundali IQ from standard, well-established facts to help with revision. This is not an official NCERT publication; always read your textbook too.