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Number Play – Class 8 Mathematics notes, important questions and MCQs
NCERT Class 8 Mathematics, chapter 5. Notes, key terms, important questions with answers and MCQs.
Chapter overview
Number puzzles use divisibility rules, place value and patterns. Knowing why a trick works is as important as using it.
Divisibility rules
- By 2: last digit even; by 5: ends in 0 or 5; by 10: ends in 0.
- By 3 / 9: sum of digits divisible by 3 / 9.
- By 4: last two digits divisible by 4; by 8: last three digits divisible by 8.
- By 11: difference between sums of alternate digits is 0 or a multiple of 11.
Number tricks with algebra
- A two-digit number ab = 10a + b; reversing gives 10b + a.
- (10a + b) + (10b + a) = 11(a + b), always divisible by 11.
- (10a + b) − (10b + a) = 9(a − b), always divisible by 9.
Key terms
- Divisible
- leaves no remainder on division
- Digit sum
- sum of all digits of a number
- Divisibility rule
- a quick test to check if one number divides another without actual division
Formulas
- ab = 10a + b
- ab + ba = 11(a + b)
Important questions with answers
Without dividing, check whether 3,795 is divisible by 5 and by 3.2 marks
It ends in 5, so it is divisible by 5. Digit sum 3 + 7 + 9 + 5 = 24, divisible by 3, so it is divisible by 3.
Why is any number of the form ABAB divisible by 101?3 marks
ABAB = 1000A + 100B + 10A + B = 1010A + 101B = 101(10A + B).
Show that the sum of a two-digit number and the number obtained by reversing its digits is always divisible by 11, and that their difference is divisible by 9. Check with 47.5 marks
Number = 10a + b; reversed = 10b + a. Sum = 11a + 11b = 11(a + b), divisible by 11. Difference = 9a − 9b = 9(a − b), divisible by 9. For 47: 47 + 74 = 121 = 11 × 11; 74 − 47 = 27 = 9 × 3.
Quick revision
- Divisible by 9 ⇔ digit sum divisible by 9.
- Reversing-and-subtracting gives a multiple of 9.
- Rule for 11 uses alternate digits.
Exam tips
- For "find the missing digit", use the digit-sum rule.
- A number divisible by both 2 and 3 is divisible by 6.
Practice MCQs
Which number is divisible by 3?
- 124
- 410
- 152
- 231
Show answer
Answer: (d) 231. 2 + 3 + 1 = 6.
A number ending in 0 is divisible by
- 10
- 7
- 3
- 9
Show answer
Answer: (a) 10. Rule for 10.
Is 6,72,104 divisible by 8?
- yes
- no
- only by 4
- cannot say
Show answer
Answer: (a) yes. Last three digits 104 = 8 × 13.
If 4x5 is divisible by 9, the digit x is
- 0
- 9
- 0 or 9
- 3
Show answer
Answer: (c) 0 or 9. 4 + x + 5 must be 9 or 18.
Which number is divisible by 9
- 4,325
- 5,551
- 6,103
- 7,281
Show answer
Answer: (d) 7,281. Digit sum 18.
The sum of a two-digit number and its reverse is always divisible by
- 9
- 10
- 7
- 11
Show answer
Answer: (d) 11. 11(a + b).
Which number is divisible by 11?
- 5731
- 9273
- 8162
- 1243
Show answer
Answer: (d) 1243. (1 + 4) − (2 + 3) = 0.
For 5A2 to be divisible by 3, the digit A can be
- 0
- 1
- 2
- 3
Show answer
Answer: (c) 2. 5 + A + 2 must be a multiple of 3; A = 2 gives 9.
All chapters of Class 8 Mathematics
Written by Kundali IQ from standard, well-established facts to help with revision. This is not an official NCERT publication; always read your textbook too.