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Relations and Functions – Class 12 Mathematics notes, important questions and MCQs

NCERT Class 12 Mathematics, chapter 1. Notes, key terms, important questions with answers and MCQs.

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Chapter overview

Relations connect elements of sets; special types (reflexive, symmetric, transitive) make equivalence relations. Functions can be one-one, onto or both (bijective).

Relations

  • Reflexive: (a, a) ∈ R for all a; symmetric: (a, b) ∈ R ⇒ (b, a) ∈ R; transitive: (a, b), (b, c) ∈ R ⇒ (a, c) ∈ R.
  • Equivalence relation = reflexive + symmetric + transitive; it partitions a set into equivalence classes.

Functions

  • One-one (injective): f(x₁) = f(x₂) ⇒ x₁ = x₂; onto (surjective): range = codomain.
  • Bijective functions have inverses; composition (g∘f)(x) = g(f(x)).
  • Number of functions from A (m elements) to B (n elements) = nᵐ; one-one functions (m ≤ n) = ⁿPₘ.

Key terms

Equivalence relation
relation that is reflexive, symmetric and transitive
Bijection
function that is both one-one and onto
Invertible function
a function f for which there is g with g∘f = identity and f∘g = identity; exists exactly when f is bijective

Formulas

  • Functions A → B: nᵐ
  • (g∘f)(x) = g(f(x))

Important questions with answers

Check whether f: ℕ → ℕ, f(x) = 2x is one-one and onto.2 marks

One-one: 2x₁ = 2x₂ gives x₁ = x₂. Not onto: odd numbers such as 1 have no pre-image in ℕ.

Show that the relation R on ℤ given by R = {(a, b): a − b is divisible by 5} is an equivalence relation.3 marks

Reflexive: a − a = 0 is divisible by 5. Symmetric: if 5 | (a − b) then 5 | (b − a) = −(a − b). Transitive: if 5 | (a − b) and 5 | (b − c), then 5 | (a − b) + (b − c) = a − c. Hence R is an equivalence relation.

Show that f: ℝ → ℝ, f(x) = 4x + 3 is invertible and find f⁻¹. Also find (f∘f)(x) and verify f∘f⁻¹ = I.5 marks

One-one: 4x₁ + 3 = 4x₂ + 3 ⇒ x₁ = x₂. Onto: for any y ∈ ℝ, x = (y − 3)/4 ∈ ℝ gives f(x) = y. So f is bijective and invertible, with f⁻¹(y) = (y − 3)/4. (f∘f)(x) = 4(4x + 3) + 3 = 16x + 15. f(f⁻¹(y)) = 4 × (y − 3)/4 + 3 = y, so f∘f⁻¹ = I.

Quick revision

  • Equivalence = R + S + T.
  • Only bijections are invertible.
  • Onto: every element of codomain has a pre-image.

Exam tips

  • f(x) = x² on ℝ is not one-one (f(2) = f(−2)); on ℕ it is.
  • To show onto, take any y in the codomain and solve f(x) = y for x inside the domain.

Practice MCQs

  1. A relation that is reflexive, symmetric and transitive is

    1. identity
    2. universal only
    3. empty
    4. equivalence
    Show answer

    Answer: (d) equivalence. Equivalence relation.

  2. f: ℝ → ℝ, f(x) = 2x + 3 is

    1. one-one only
    2. onto only
    3. bijective
    4. neither
    Show answer

    Answer: (c) bijective. Linear with non-zero slope.

  3. f(x) = x² from ℝ to ℝ is

    1. one-one
    2. onto
    3. neither one-one nor onto
    4. bijective
    Show answer

    Answer: (c) neither one-one nor onto. f(1) = f(−1) and negatives have no pre-image.

  4. If f(x) = x + 1 and g(x) = 2x, then (g∘f)(3) is

    1. 7
    2. 6
    3. 8
    4. 10
    Show answer

    Answer: (c) 8. g(4) = 8.

  5. Number of reflexive relations on a set with 3 elements is

    1. 2⁶
    2. 2⁹
    3. 2³
    4. 3²
    Show answer

    Answer: (a) 2⁶. Diagonal fixed; 6 other pairs free.

  6. Number of functions from a set of 3 elements to a set of 2 elements is

    1. 6
    2. 9
    3. 8
    4. 5
    Show answer

    Answer: (c) 8. 2³.

  7. Relation R on {1, 2, 3} given by R = {(1, 1), (2, 2), (3, 3), (1, 2)} is

    1. reflexive and transitive but not symmetric
    2. equivalence
    3. symmetric only
    4. not reflexive
    Show answer

    Answer: (a) reflexive and transitive but not symmetric. (2, 1) missing.

  8. If f(x) = (3x + 2)/(x − 1), x ≠ 1, then f⁻¹(x) is

    1. (x + 3)/(x − 2)
    2. (x − 2)/(x + 3)
    3. (x + 2)/(x − 3)
    4. (3x − 2)/(x + 1)
    Show answer

    Answer: (c) (x + 2)/(x − 3). Solve y = (3x + 2)/(x − 1) for x.

All chapters of Class 12 Mathematics

Written by Kundali IQ from standard, well-established facts to help with revision. This is not an official NCERT publication; always read your textbook too.