Square of a sum
(a + b)² = a² + 2ab + b²
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(a + b)² = a² + 2ab + b²
(a − b)² = a² − 2ab + b²
a² − b² = (a + b)(a − b)
(a + b)³ = a³ + b³ + 3ab(a + b)
(a − b)³ = a³ − b³ − 3ab(a − b)
a³ + b³ = (a + b)(a² − ab + b²)
a³ + b³ + c³ − 3abc = (a + b + c)(a² + b² + c² − ab − bc − ca)
If a + b + c = 0, a³ + b³ + c³ = 3abc
x = [−b ± √(b² − 4ac)] / 2a
D = b² − 4ac decides the roots
α + β = −b/a, αβ = c/a
aₙ = a + (n − 1)d, Sₙ = n/2[2a + (n − 1)d]
aₙ = arⁿ⁻¹, Sₙ = a(rⁿ − 1)/(r − 1)
aᵐ·aⁿ = aᵐ⁺ⁿ; aᵐ/aⁿ = aᵐ⁻ⁿ; (aᵐ)ⁿ = aᵐⁿ
a⁰ = 1
log(mn) = log m + log n; log(m/n) = log m − log n; log mⁿ = n log m
logₐ b = log b / log a